Anning (China), April 24: India's top women's singles player Ankita Raina shocked former US Open champion Samantha Stosur for the biggest win of her career, progressing to the second round of Kunping Open here on Wednesday (April 23).
The Indian, an Asian Games bronze medallist, shocked the fancied Australian 7-5, 2-6, 6-5 in a gruelling two hours and fifty minutes battle at the WTA 125K event. This is the second time the two faced off, with Stosur winning their last encounter in straight sets.
The 26-year-old Indian struggled to hold her and managed only three aces throughout the match compared to Stosur, who smashed seven aces. However, the world no 77 made more errors -- 18 double faults -- compared to Ankita's six. She will face Kai-Lin Zhang of China in the second round.
Upset Alert ⚠— IndInTokyo'2020 (@India_Olym2020) April 24, 2019
Big news coming in from the tennis court 🎾
India No 1 @ankita_champ defeats Aus 🇦🇺 great Samantha Stosur, FWR 4 in Anning 125k. Samantha had 18 Double Faults
Must be the biggest win for our champ Ankita Raina
Great Show!!#Tennis 🎾 #Anning@IndiantennisFan pic.twitter.com/0n6OldNHeD
Raina, ranked 178, had finished runner up at the USD 60,000 ITF event in Istanbul earlier this month. Last year, she became only the third Indian woman tennis player after Sania Mirza and Nirupama Vaidyanathan to breach the top-200 rankings in singles.
Stosur had won the 2011 US Open defeating Serena Williams in the final. She is a former world No. 1 in doubles and has won six other grand slam titles, including 2005 US Open, 2006 French Open, and 2019 Australian Open women's doubles events, and the 2005 Australian Open, 2008 Wimbledon Championships and 2014 Wimbledon Championships mixed doubles events.